1/x+3x+12/x^2-5=7x-56/x^2-5x

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Solution for 1/x+3x+12/x^2-5=7x-56/x^2-5x equation: 



1/x+3x+12/x^2-5=7x-56/x^2-5x

We move all terms to the left:

1/x+3x+12/x^2-5-(7x-56/x^2-5x)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x^2-5x)!=0

x∈R



We add all the numbers together, and all the variables

3x+1/x+12/x^2-(7x-56/x^2-5x)-5=0

We get rid of parentheses

3x+1/x+12/x^2-7x+56/x^2+5x-5=0

We calculate fractions

We do not support expression: x^3

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